Optimal. Leaf size=259 \[ \frac{3 \sqrt{\frac{\pi }{2}} a \sqrt{a^2+x^2} \text{Erf}\left (\sqrt{2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}\right )}{64 \sqrt{\frac{x^2}{a^2}+1}}+\frac{3 \sqrt{\frac{\pi }{2}} a \sqrt{a^2+x^2} \text{Erfi}\left (\sqrt{2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}\right )}{64 \sqrt{\frac{x^2}{a^2}+1}}+\frac{a \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{5/2}}{5 \sqrt{\frac{x^2}{a^2}+1}}+\frac{1}{2} x \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}-\frac{3 x^2 \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{8 a \sqrt{\frac{x^2}{a^2}+1}}-\frac{3 a \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{16 \sqrt{\frac{x^2}{a^2}+1}} \]
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Rubi [A] time = 0.275563, antiderivative size = 259, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 9, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.409, Rules used = {5682, 5675, 5663, 5779, 3312, 3307, 2180, 2204, 2205} \[ \frac{3 \sqrt{\frac{\pi }{2}} a \sqrt{a^2+x^2} \text{Erf}\left (\sqrt{2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}\right )}{64 \sqrt{\frac{x^2}{a^2}+1}}+\frac{3 \sqrt{\frac{\pi }{2}} a \sqrt{a^2+x^2} \text{Erfi}\left (\sqrt{2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}\right )}{64 \sqrt{\frac{x^2}{a^2}+1}}+\frac{a \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{5/2}}{5 \sqrt{\frac{x^2}{a^2}+1}}+\frac{1}{2} x \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}-\frac{3 x^2 \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{8 a \sqrt{\frac{x^2}{a^2}+1}}-\frac{3 a \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{16 \sqrt{\frac{x^2}{a^2}+1}} \]
Antiderivative was successfully verified.
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Rule 5682
Rule 5675
Rule 5663
Rule 5779
Rule 3312
Rule 3307
Rule 2180
Rule 2204
Rule 2205
Rubi steps
\begin{align*} \int \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2} \, dx &=\frac{1}{2} x \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}+\frac{\sqrt{a^2+x^2} \int \frac{\sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}}{\sqrt{1+\frac{x^2}{a^2}}} \, dx}{2 \sqrt{1+\frac{x^2}{a^2}}}-\frac{\left (3 \sqrt{a^2+x^2}\right ) \int x \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )} \, dx}{4 a \sqrt{1+\frac{x^2}{a^2}}}\\ &=-\frac{3 x^2 \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{8 a \sqrt{1+\frac{x^2}{a^2}}}+\frac{1}{2} x \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}+\frac{a \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{5/2}}{5 \sqrt{1+\frac{x^2}{a^2}}}+\frac{\left (3 \sqrt{a^2+x^2}\right ) \int \frac{x^2}{\sqrt{1+\frac{x^2}{a^2}} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}} \, dx}{16 a^2 \sqrt{1+\frac{x^2}{a^2}}}\\ &=-\frac{3 x^2 \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{8 a \sqrt{1+\frac{x^2}{a^2}}}+\frac{1}{2} x \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}+\frac{a \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{5/2}}{5 \sqrt{1+\frac{x^2}{a^2}}}+\frac{\left (3 a \sqrt{a^2+x^2}\right ) \operatorname{Subst}\left (\int \frac{\sinh ^2(x)}{\sqrt{x}} \, dx,x,\sinh ^{-1}\left (\frac{x}{a}\right )\right )}{16 \sqrt{1+\frac{x^2}{a^2}}}\\ &=-\frac{3 x^2 \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{8 a \sqrt{1+\frac{x^2}{a^2}}}+\frac{1}{2} x \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}+\frac{a \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{5/2}}{5 \sqrt{1+\frac{x^2}{a^2}}}-\frac{\left (3 a \sqrt{a^2+x^2}\right ) \operatorname{Subst}\left (\int \left (\frac{1}{2 \sqrt{x}}-\frac{\cosh (2 x)}{2 \sqrt{x}}\right ) \, dx,x,\sinh ^{-1}\left (\frac{x}{a}\right )\right )}{16 \sqrt{1+\frac{x^2}{a^2}}}\\ &=-\frac{3 a \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{16 \sqrt{1+\frac{x^2}{a^2}}}-\frac{3 x^2 \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{8 a \sqrt{1+\frac{x^2}{a^2}}}+\frac{1}{2} x \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}+\frac{a \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{5/2}}{5 \sqrt{1+\frac{x^2}{a^2}}}+\frac{\left (3 a \sqrt{a^2+x^2}\right ) \operatorname{Subst}\left (\int \frac{\cosh (2 x)}{\sqrt{x}} \, dx,x,\sinh ^{-1}\left (\frac{x}{a}\right )\right )}{32 \sqrt{1+\frac{x^2}{a^2}}}\\ &=-\frac{3 a \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{16 \sqrt{1+\frac{x^2}{a^2}}}-\frac{3 x^2 \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{8 a \sqrt{1+\frac{x^2}{a^2}}}+\frac{1}{2} x \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}+\frac{a \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{5/2}}{5 \sqrt{1+\frac{x^2}{a^2}}}+\frac{\left (3 a \sqrt{a^2+x^2}\right ) \operatorname{Subst}\left (\int \frac{e^{-2 x}}{\sqrt{x}} \, dx,x,\sinh ^{-1}\left (\frac{x}{a}\right )\right )}{64 \sqrt{1+\frac{x^2}{a^2}}}+\frac{\left (3 a \sqrt{a^2+x^2}\right ) \operatorname{Subst}\left (\int \frac{e^{2 x}}{\sqrt{x}} \, dx,x,\sinh ^{-1}\left (\frac{x}{a}\right )\right )}{64 \sqrt{1+\frac{x^2}{a^2}}}\\ &=-\frac{3 a \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{16 \sqrt{1+\frac{x^2}{a^2}}}-\frac{3 x^2 \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{8 a \sqrt{1+\frac{x^2}{a^2}}}+\frac{1}{2} x \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}+\frac{a \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{5/2}}{5 \sqrt{1+\frac{x^2}{a^2}}}+\frac{\left (3 a \sqrt{a^2+x^2}\right ) \operatorname{Subst}\left (\int e^{-2 x^2} \, dx,x,\sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}\right )}{32 \sqrt{1+\frac{x^2}{a^2}}}+\frac{\left (3 a \sqrt{a^2+x^2}\right ) \operatorname{Subst}\left (\int e^{2 x^2} \, dx,x,\sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}\right )}{32 \sqrt{1+\frac{x^2}{a^2}}}\\ &=-\frac{3 a \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{16 \sqrt{1+\frac{x^2}{a^2}}}-\frac{3 x^2 \sqrt{a^2+x^2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}}{8 a \sqrt{1+\frac{x^2}{a^2}}}+\frac{1}{2} x \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{3/2}+\frac{a \sqrt{a^2+x^2} \sinh ^{-1}\left (\frac{x}{a}\right )^{5/2}}{5 \sqrt{1+\frac{x^2}{a^2}}}+\frac{3 a \sqrt{\frac{\pi }{2}} \sqrt{a^2+x^2} \text{erf}\left (\sqrt{2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}\right )}{64 \sqrt{1+\frac{x^2}{a^2}}}+\frac{3 a \sqrt{\frac{\pi }{2}} \sqrt{a^2+x^2} \text{erfi}\left (\sqrt{2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}\right )}{64 \sqrt{1+\frac{x^2}{a^2}}}\\ \end{align*}
Mathematica [A] time = 0.24483, size = 133, normalized size = 0.51 \[ \frac{a \sqrt{a^2+x^2} \left (15 \sqrt{2 \pi } \text{Erf}\left (\sqrt{2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}\right )+15 \sqrt{2 \pi } \text{Erfi}\left (\sqrt{2} \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )}\right )+8 \sqrt{\sinh ^{-1}\left (\frac{x}{a}\right )} \left (16 \sinh ^{-1}\left (\frac{x}{a}\right )^2+20 \sinh \left (2 \sinh ^{-1}\left (\frac{x}{a}\right )\right ) \sinh ^{-1}\left (\frac{x}{a}\right )-15 \cosh \left (2 \sinh ^{-1}\left (\frac{x}{a}\right )\right )\right )\right )}{640 \sqrt{\frac{x^2}{a^2}+1}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.214, size = 0, normalized size = 0. \begin{align*} \int \left ({\it Arcsinh} \left ({\frac{x}{a}} \right ) \right ) ^{{\frac{3}{2}}}\sqrt{{a}^{2}+{x}^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{a^{2} + x^{2}} \operatorname{arsinh}\left (\frac{x}{a}\right )^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{a^{2} + x^{2}} \operatorname{arsinh}\left (\frac{x}{a}\right )^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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